mirror of
https://github.com/arsenetar/dupeguru.git
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834 lines
28 KiB
Python
834 lines
28 KiB
Python
# Created By: Virgil Dupras
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# Created On: 2006/01/29
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# Copyright 2013 Hardcoded Software (http://www.hardcoded.net)
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#
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# This software is licensed under the "BSD" License as described in the "LICENSE" file,
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# which should be included with this package. The terms are also available at
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# http://www.hardcoded.net/licenses/bsd_license
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import sys
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from jobprogress import job
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from hscommon.util import first
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from hscommon.testutil import eq_, log_calls
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from .base import NamedObject
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from .. import engine
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from ..engine import *
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no = NamedObject
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def get_match_triangle():
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o1 = NamedObject(with_words=True)
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o2 = NamedObject(with_words=True)
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o3 = NamedObject(with_words=True)
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m1 = get_match(o1,o2)
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m2 = get_match(o1,o3)
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m3 = get_match(o2,o3)
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return [m1, m2, m3]
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def get_test_group():
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m1, m2, m3 = get_match_triangle()
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result = Group()
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result.add_match(m1)
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result.add_match(m2)
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result.add_match(m3)
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return result
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def assert_match(m, name1, name2):
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# When testing matches, whether objects are in first or second position very often doesn't
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# matter. This function makes this test more convenient.
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if m.first.name == name1:
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eq_(m.second.name, name2)
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else:
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eq_(m.first.name, name2)
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eq_(m.second.name, name1)
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class TestCasegetwords:
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def test_spaces(self):
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eq_(['a', 'b', 'c', 'd'], getwords("a b c d"))
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eq_(['a', 'b', 'c', 'd'], getwords(" a b c d "))
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def test_splitter_chars(self):
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eq_(
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[chr(i) for i in range(ord('a'),ord('z')+1)],
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getwords("a-b_c&d+e(f)g;h\\i[j]k{l}m:n.o,p<q>r/s?t~u!v@w#x$y*z")
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)
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def test_joiner_chars(self):
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eq_(["aec"], getwords("a'e\u0301c"))
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def test_empty(self):
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eq_([], getwords(''))
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def test_returns_lowercase(self):
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eq_(['foo', 'bar'], getwords('FOO BAR'))
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def test_decompose_unicode(self):
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eq_(getwords('foo\xe9bar'), ['fooebar'])
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class TestCasegetfields:
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def test_simple(self):
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eq_([['a', 'b'], ['c', 'd', 'e']], getfields('a b - c d e'))
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def test_empty(self):
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eq_([], getfields(''))
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def test_cleans_empty_fields(self):
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expected = [['a', 'bc', 'def']]
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actual = getfields(' - a bc def')
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eq_(expected, actual)
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expected = [['bc', 'def']]
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class TestCaseunpack_fields:
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def test_with_fields(self):
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expected = ['a', 'b', 'c', 'd', 'e', 'f']
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actual = unpack_fields([['a'], ['b', 'c'], ['d', 'e', 'f']])
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eq_(expected, actual)
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def test_without_fields(self):
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expected = ['a', 'b', 'c', 'd', 'e', 'f']
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actual = unpack_fields(['a', 'b', 'c', 'd', 'e', 'f'])
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eq_(expected, actual)
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def test_empty(self):
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eq_([], unpack_fields([]))
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class TestCaseWordCompare:
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def test_list(self):
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eq_(100, compare(['a', 'b', 'c', 'd'],['a', 'b', 'c', 'd']))
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eq_(86, compare(['a', 'b', 'c', 'd'],['a', 'b', 'c']))
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def test_unordered(self):
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#Sometimes, users don't want fuzzy matching too much When they set the slider
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#to 100, they don't expect a filename with the same words, but not the same order, to match.
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#Thus, we want to return 99 in that case.
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eq_(99, compare(['a', 'b', 'c', 'd'], ['d', 'b', 'c', 'a']))
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def test_word_occurs_twice(self):
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#if a word occurs twice in first, but once in second, we want the word to be only counted once
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eq_(89, compare(['a', 'b', 'c', 'd', 'a'], ['d', 'b', 'c', 'a']))
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def test_uses_copy_of_lists(self):
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first = ['foo', 'bar']
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second = ['bar', 'bleh']
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compare(first, second)
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eq_(['foo', 'bar'], first)
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eq_(['bar', 'bleh'], second)
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def test_word_weight(self):
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eq_(int((6.0 / 13.0) * 100), compare(['foo', 'bar'], ['bar', 'bleh'], (WEIGHT_WORDS, )))
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def test_similar_words(self):
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eq_(100, compare(['the', 'white', 'stripes'],['the', 'whites', 'stripe'], (MATCH_SIMILAR_WORDS, )))
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def test_empty(self):
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eq_(0, compare([], []))
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def test_with_fields(self):
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eq_(67, compare([['a', 'b'], ['c', 'd', 'e']], [['a', 'b'], ['c', 'd', 'f']]))
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def test_propagate_flags_with_fields(self, monkeypatch):
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def mock_compare(first, second, flags):
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eq_((0, 1, 2, 3, 5), flags)
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monkeypatch.setattr(engine, 'compare_fields', mock_compare)
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compare([['a']], [['a']], (0, 1, 2, 3, 5))
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class TestCaseWordCompareWithFields:
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def test_simple(self):
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eq_(67, compare_fields([['a', 'b'], ['c', 'd', 'e']], [['a', 'b'], ['c', 'd', 'f']]))
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def test_empty(self):
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eq_(0, compare_fields([], []))
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def test_different_length(self):
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eq_(0, compare_fields([['a'], ['b']], [['a'], ['b'], ['c']]))
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def test_propagates_flags(self, monkeypatch):
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def mock_compare(first, second, flags):
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eq_((0, 1, 2, 3, 5), flags)
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monkeypatch.setattr(engine, 'compare_fields', mock_compare)
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compare_fields([['a']], [['a']],(0, 1, 2, 3, 5))
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def test_order(self):
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first = [['a', 'b'], ['c', 'd', 'e']]
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second = [['c', 'd', 'f'], ['a', 'b']]
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eq_(0, compare_fields(first, second))
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def test_no_order(self):
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first = [['a','b'],['c','d','e']]
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second = [['c','d','f'],['a','b']]
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eq_(67, compare_fields(first, second, (NO_FIELD_ORDER, )))
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first = [['a','b'],['a','b']] #a field can only be matched once.
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second = [['c','d','f'],['a','b']]
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eq_(0, compare_fields(first, second, (NO_FIELD_ORDER, )))
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first = [['a','b'],['a','b','c']]
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second = [['c','d','f'],['a','b']]
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eq_(33, compare_fields(first, second, (NO_FIELD_ORDER, )))
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def test_compare_fields_without_order_doesnt_alter_fields(self):
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#The NO_ORDER comp type altered the fields!
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first = [['a','b'],['c','d','e']]
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second = [['c','d','f'],['a','b']]
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eq_(67, compare_fields(first, second, (NO_FIELD_ORDER, )))
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eq_([['a','b'],['c','d','e']],first)
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eq_([['c','d','f'],['a','b']],second)
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class TestCasebuild_word_dict:
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def test_with_standard_words(self):
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l = [NamedObject('foo bar',True)]
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l.append(NamedObject('bar baz',True))
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l.append(NamedObject('baz bleh foo',True))
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d = build_word_dict(l)
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eq_(4,len(d))
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eq_(2,len(d['foo']))
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assert l[0] in d['foo']
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assert l[2] in d['foo']
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eq_(2,len(d['bar']))
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assert l[0] in d['bar']
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assert l[1] in d['bar']
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eq_(2,len(d['baz']))
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assert l[1] in d['baz']
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assert l[2] in d['baz']
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eq_(1,len(d['bleh']))
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assert l[2] in d['bleh']
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def test_unpack_fields(self):
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o = NamedObject('')
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o.words = [['foo','bar'],['baz']]
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d = build_word_dict([o])
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eq_(3,len(d))
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eq_(1,len(d['foo']))
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def test_words_are_unaltered(self):
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o = NamedObject('')
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o.words = [['foo','bar'],['baz']]
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build_word_dict([o])
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eq_([['foo','bar'],['baz']],o.words)
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def test_object_instances_can_only_be_once_in_words_object_list(self):
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o = NamedObject('foo foo',True)
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d = build_word_dict([o])
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eq_(1,len(d['foo']))
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def test_job(self):
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def do_progress(p,d=''):
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self.log.append(p)
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return True
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j = job.Job(1,do_progress)
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self.log = []
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s = "foo bar"
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build_word_dict([NamedObject(s, True), NamedObject(s, True), NamedObject(s, True)], j)
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# We don't have intermediate log because iter_with_progress is called with every > 1
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eq_(0,self.log[0])
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eq_(100,self.log[1])
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class TestCasemerge_similar_words:
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def test_some_similar_words(self):
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d = {
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'foobar':set([1]),
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'foobar1':set([2]),
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'foobar2':set([3]),
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}
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merge_similar_words(d)
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eq_(1,len(d))
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eq_(3,len(d['foobar']))
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class TestCasereduce_common_words:
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def test_typical(self):
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d = {
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'foo': set([NamedObject('foo bar',True) for i in range(50)]),
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'bar': set([NamedObject('foo bar',True) for i in range(49)])
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}
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reduce_common_words(d, 50)
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assert 'foo' not in d
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eq_(49,len(d['bar']))
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def test_dont_remove_objects_with_only_common_words(self):
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d = {
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'common': set([NamedObject("common uncommon",True) for i in range(50)] + [NamedObject("common",True)]),
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'uncommon': set([NamedObject("common uncommon",True)])
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}
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reduce_common_words(d, 50)
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eq_(1,len(d['common']))
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eq_(1,len(d['uncommon']))
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def test_values_still_are_set_instances(self):
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d = {
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'common': set([NamedObject("common uncommon",True) for i in range(50)] + [NamedObject("common",True)]),
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'uncommon': set([NamedObject("common uncommon",True)])
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}
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reduce_common_words(d, 50)
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assert isinstance(d['common'],set)
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assert isinstance(d['uncommon'],set)
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def test_dont_raise_KeyError_when_a_word_has_been_removed(self):
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#If a word has been removed by the reduce, an object in a subsequent common word that
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#contains the word that has been removed would cause a KeyError.
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d = {
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'foo': set([NamedObject('foo bar baz',True) for i in range(50)]),
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'bar': set([NamedObject('foo bar baz',True) for i in range(50)]),
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'baz': set([NamedObject('foo bar baz',True) for i in range(49)])
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}
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try:
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reduce_common_words(d, 50)
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except KeyError:
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self.fail()
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def test_unpack_fields(self):
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#object.words may be fields.
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def create_it():
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o = NamedObject('')
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o.words = [['foo','bar'],['baz']]
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return o
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d = {
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'foo': set([create_it() for i in range(50)])
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}
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try:
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reduce_common_words(d, 50)
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except TypeError:
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self.fail("must support fields.")
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def test_consider_a_reduced_common_word_common_even_after_reduction(self):
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#There was a bug in the code that causeda word that has already been reduced not to
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#be counted as a common word for subsequent words. For example, if 'foo' is processed
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#as a common word, keeping a "foo bar" file in it, and the 'bar' is processed, "foo bar"
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#would not stay in 'bar' because 'foo' is not a common word anymore.
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only_common = NamedObject('foo bar',True)
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d = {
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'foo': set([NamedObject('foo bar baz',True) for i in range(49)] + [only_common]),
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'bar': set([NamedObject('foo bar baz',True) for i in range(49)] + [only_common]),
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'baz': set([NamedObject('foo bar baz',True) for i in range(49)])
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}
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reduce_common_words(d, 50)
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eq_(1,len(d['foo']))
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eq_(1,len(d['bar']))
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eq_(49,len(d['baz']))
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class TestCaseget_match:
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def test_simple(self):
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o1 = NamedObject("foo bar",True)
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o2 = NamedObject("bar bleh",True)
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m = get_match(o1,o2)
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eq_(50,m.percentage)
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eq_(['foo','bar'],m.first.words)
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eq_(['bar','bleh'],m.second.words)
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assert m.first is o1
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assert m.second is o2
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def test_in(self):
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o1 = NamedObject("foo",True)
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o2 = NamedObject("bar",True)
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m = get_match(o1,o2)
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assert o1 in m
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assert o2 in m
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assert object() not in m
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def test_word_weight(self):
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eq_(int((6.0 / 13.0) * 100),get_match(NamedObject("foo bar",True),NamedObject("bar bleh",True),(WEIGHT_WORDS,)).percentage)
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class TestCaseGetMatches:
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def test_empty(self):
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eq_(getmatches([]), [])
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def test_simple(self):
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l = [NamedObject("foo bar"),NamedObject("bar bleh"),NamedObject("a b c foo")]
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r = getmatches(l)
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eq_(2,len(r))
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m = first(m for m in r if m.percentage == 50) #"foo bar" and "bar bleh"
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assert_match(m, 'foo bar', 'bar bleh')
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m = first(m for m in r if m.percentage == 33) #"foo bar" and "a b c foo"
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assert_match(m, 'foo bar', 'a b c foo')
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def test_null_and_unrelated_objects(self):
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l = [NamedObject("foo bar"),NamedObject("bar bleh"),NamedObject(""),NamedObject("unrelated object")]
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r = getmatches(l)
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eq_(len(r), 1)
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m = r[0]
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eq_(m.percentage, 50)
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assert_match(m, 'foo bar', 'bar bleh')
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def test_twice_the_same_word(self):
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l = [NamedObject("foo foo bar"),NamedObject("bar bleh")]
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r = getmatches(l)
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eq_(1,len(r))
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def test_twice_the_same_word_when_preworded(self):
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l = [NamedObject("foo foo bar",True),NamedObject("bar bleh",True)]
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r = getmatches(l)
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eq_(1,len(r))
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def test_two_words_match(self):
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l = [NamedObject("foo bar"),NamedObject("foo bar bleh")]
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r = getmatches(l)
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eq_(1,len(r))
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def test_match_files_with_only_common_words(self):
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#If a word occurs more than 50 times, it is excluded from the matching process
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#The problem with the common_word_threshold is that the files containing only common
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#words will never be matched together. We *should* match them.
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# This test assumes that the common word threashold const is 50
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l = [NamedObject("foo") for i in range(50)]
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r = getmatches(l)
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eq_(1225,len(r))
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def test_use_words_already_there_if_there(self):
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o1 = NamedObject('foo')
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o2 = NamedObject('bar')
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o2.words = ['foo']
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eq_(1, len(getmatches([o1,o2])))
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def test_job(self):
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def do_progress(p,d=''):
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self.log.append(p)
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return True
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j = job.Job(1,do_progress)
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self.log = []
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s = "foo bar"
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getmatches([NamedObject(s), NamedObject(s), NamedObject(s)], j=j)
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assert len(self.log) > 2
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eq_(0,self.log[0])
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eq_(100,self.log[-1])
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def test_weight_words(self):
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l = [NamedObject("foo bar"),NamedObject("bar bleh")]
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m = getmatches(l, weight_words=True)[0]
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eq_(int((6.0 / 13.0) * 100),m.percentage)
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def test_similar_word(self):
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l = [NamedObject("foobar"),NamedObject("foobars")]
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eq_(len(getmatches(l, match_similar_words=True)), 1)
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eq_(getmatches(l, match_similar_words=True)[0].percentage, 100)
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l = [NamedObject("foobar"),NamedObject("foo")]
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eq_(len(getmatches(l, match_similar_words=True)), 0) #too far
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l = [NamedObject("bizkit"),NamedObject("bizket")]
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eq_(len(getmatches(l, match_similar_words=True)), 1)
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l = [NamedObject("foobar"),NamedObject("foosbar")]
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eq_(len(getmatches(l, match_similar_words=True)), 1)
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def test_single_object_with_similar_words(self):
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l = [NamedObject("foo foos")]
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eq_(len(getmatches(l, match_similar_words=True)), 0)
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def test_double_words_get_counted_only_once(self):
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l = [NamedObject("foo bar foo bleh"),NamedObject("foo bar bleh bar")]
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m = getmatches(l)[0]
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eq_(75,m.percentage)
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def test_with_fields(self):
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o1 = NamedObject("foo bar - foo bleh")
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o2 = NamedObject("foo bar - bleh bar")
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o1.words = getfields(o1.name)
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o2.words = getfields(o2.name)
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m = getmatches([o1, o2])[0]
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eq_(50, m.percentage)
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def test_with_fields_no_order(self):
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o1 = NamedObject("foo bar - foo bleh")
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o2 = NamedObject("bleh bang - foo bar")
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o1.words = getfields(o1.name)
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o2.words = getfields(o2.name)
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m = getmatches([o1, o2], no_field_order=True)[0]
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eq_(m.percentage, 50)
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def test_only_match_similar_when_the_option_is_set(self):
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l = [NamedObject("foobar"),NamedObject("foobars")]
|
|
eq_(len(getmatches(l, match_similar_words=False)), 0)
|
|
|
|
def test_dont_recurse_do_match(self):
|
|
# with nosetests, the stack is increased. The number has to be high enough not to be failing falsely
|
|
sys.setrecursionlimit(100)
|
|
files = [NamedObject('foo bar') for i in range(101)]
|
|
try:
|
|
getmatches(files)
|
|
except RuntimeError:
|
|
self.fail()
|
|
finally:
|
|
sys.setrecursionlimit(1000)
|
|
|
|
def test_min_match_percentage(self):
|
|
l = [NamedObject("foo bar"),NamedObject("bar bleh"),NamedObject("a b c foo")]
|
|
r = getmatches(l, min_match_percentage=50)
|
|
eq_(1,len(r)) #Only "foo bar" / "bar bleh" should match
|
|
|
|
def test_MemoryError(self, monkeypatch):
|
|
@log_calls
|
|
def mocked_match(first, second, flags):
|
|
if len(mocked_match.calls) > 42:
|
|
raise MemoryError()
|
|
return Match(first, second, 0)
|
|
|
|
objects = [NamedObject() for i in range(10)] # results in 45 matches
|
|
monkeypatch.setattr(engine, 'get_match', mocked_match)
|
|
try:
|
|
r = getmatches(objects)
|
|
except MemoryError:
|
|
self.fail('MemorryError must be handled')
|
|
eq_(42, len(r))
|
|
|
|
|
|
class TestCaseGetMatchesByContents:
|
|
def test_dont_compare_empty_files(self):
|
|
o1, o2 = no(size=0), no(size=0)
|
|
assert not getmatches_by_contents([o1, o2])
|
|
|
|
|
|
class TestCaseGroup:
|
|
def test_empy(self):
|
|
g = Group()
|
|
eq_(None,g.ref)
|
|
eq_([],g.dupes)
|
|
eq_(0,len(g.matches))
|
|
|
|
def test_add_match(self):
|
|
g = Group()
|
|
m = get_match(NamedObject("foo",True),NamedObject("bar",True))
|
|
g.add_match(m)
|
|
assert g.ref is m.first
|
|
eq_([m.second],g.dupes)
|
|
eq_(1,len(g.matches))
|
|
assert m in g.matches
|
|
|
|
def test_multiple_add_match(self):
|
|
g = Group()
|
|
o1 = NamedObject("a",True)
|
|
o2 = NamedObject("b",True)
|
|
o3 = NamedObject("c",True)
|
|
o4 = NamedObject("d",True)
|
|
g.add_match(get_match(o1,o2))
|
|
assert g.ref is o1
|
|
eq_([o2],g.dupes)
|
|
eq_(1,len(g.matches))
|
|
g.add_match(get_match(o1,o3))
|
|
eq_([o2],g.dupes)
|
|
eq_(2,len(g.matches))
|
|
g.add_match(get_match(o2,o3))
|
|
eq_([o2,o3],g.dupes)
|
|
eq_(3,len(g.matches))
|
|
g.add_match(get_match(o1,o4))
|
|
eq_([o2,o3],g.dupes)
|
|
eq_(4,len(g.matches))
|
|
g.add_match(get_match(o2,o4))
|
|
eq_([o2,o3],g.dupes)
|
|
eq_(5,len(g.matches))
|
|
g.add_match(get_match(o3,o4))
|
|
eq_([o2,o3,o4],g.dupes)
|
|
eq_(6,len(g.matches))
|
|
|
|
def test_len(self):
|
|
g = Group()
|
|
eq_(0,len(g))
|
|
g.add_match(get_match(NamedObject("foo",True),NamedObject("bar",True)))
|
|
eq_(2,len(g))
|
|
|
|
def test_add_same_match_twice(self):
|
|
g = Group()
|
|
m = get_match(NamedObject("foo",True),NamedObject("foo",True))
|
|
g.add_match(m)
|
|
eq_(2,len(g))
|
|
eq_(1,len(g.matches))
|
|
g.add_match(m)
|
|
eq_(2,len(g))
|
|
eq_(1,len(g.matches))
|
|
|
|
def test_in(self):
|
|
g = Group()
|
|
o1 = NamedObject("foo",True)
|
|
o2 = NamedObject("bar",True)
|
|
assert o1 not in g
|
|
g.add_match(get_match(o1,o2))
|
|
assert o1 in g
|
|
assert o2 in g
|
|
|
|
def test_remove(self):
|
|
g = Group()
|
|
o1 = NamedObject("foo",True)
|
|
o2 = NamedObject("bar",True)
|
|
o3 = NamedObject("bleh",True)
|
|
g.add_match(get_match(o1,o2))
|
|
g.add_match(get_match(o1,o3))
|
|
g.add_match(get_match(o2,o3))
|
|
eq_(3,len(g.matches))
|
|
eq_(3,len(g))
|
|
g.remove_dupe(o3)
|
|
eq_(1,len(g.matches))
|
|
eq_(2,len(g))
|
|
g.remove_dupe(o1)
|
|
eq_(0,len(g.matches))
|
|
eq_(0,len(g))
|
|
|
|
def test_remove_with_ref_dupes(self):
|
|
g = Group()
|
|
o1 = NamedObject("foo",True)
|
|
o2 = NamedObject("bar",True)
|
|
o3 = NamedObject("bleh",True)
|
|
g.add_match(get_match(o1,o2))
|
|
g.add_match(get_match(o1,o3))
|
|
g.add_match(get_match(o2,o3))
|
|
o1.is_ref = True
|
|
o2.is_ref = True
|
|
g.remove_dupe(o3)
|
|
eq_(0,len(g))
|
|
|
|
def test_switch_ref(self):
|
|
o1 = NamedObject(with_words=True)
|
|
o2 = NamedObject(with_words=True)
|
|
g = Group()
|
|
g.add_match(get_match(o1,o2))
|
|
assert o1 is g.ref
|
|
g.switch_ref(o2)
|
|
assert o2 is g.ref
|
|
eq_([o1],g.dupes)
|
|
g.switch_ref(o2)
|
|
assert o2 is g.ref
|
|
g.switch_ref(NamedObject('',True))
|
|
assert o2 is g.ref
|
|
|
|
def test_switch_ref_from_ref_dir(self):
|
|
# When the ref dupe is from a ref dir, switch_ref() does nothing
|
|
o1 = no(with_words=True)
|
|
o2 = no(with_words=True)
|
|
o1.is_ref = True
|
|
g = Group()
|
|
g.add_match(get_match(o1, o2))
|
|
g.switch_ref(o2)
|
|
assert o1 is g.ref
|
|
|
|
def test_get_match_of(self):
|
|
g = Group()
|
|
for m in get_match_triangle():
|
|
g.add_match(m)
|
|
o = g.dupes[0]
|
|
m = g.get_match_of(o)
|
|
assert g.ref in m
|
|
assert o in m
|
|
assert g.get_match_of(NamedObject('',True)) is None
|
|
assert g.get_match_of(g.ref) is None
|
|
|
|
def test_percentage(self):
|
|
#percentage should return the avg percentage in relation to the ref
|
|
m1,m2,m3 = get_match_triangle()
|
|
m1 = Match(m1[0], m1[1], 100)
|
|
m2 = Match(m2[0], m2[1], 50)
|
|
m3 = Match(m3[0], m3[1], 33)
|
|
g = Group()
|
|
g.add_match(m1)
|
|
g.add_match(m2)
|
|
g.add_match(m3)
|
|
eq_(75,g.percentage)
|
|
g.switch_ref(g.dupes[0])
|
|
eq_(66,g.percentage)
|
|
g.remove_dupe(g.dupes[0])
|
|
eq_(33,g.percentage)
|
|
g.add_match(m1)
|
|
g.add_match(m2)
|
|
eq_(66,g.percentage)
|
|
|
|
def test_percentage_on_empty_group(self):
|
|
g = Group()
|
|
eq_(0,g.percentage)
|
|
|
|
def test_prioritize(self):
|
|
m1,m2,m3 = get_match_triangle()
|
|
o1 = m1.first
|
|
o2 = m1.second
|
|
o3 = m2.second
|
|
o1.name = 'c'
|
|
o2.name = 'b'
|
|
o3.name = 'a'
|
|
g = Group()
|
|
g.add_match(m1)
|
|
g.add_match(m2)
|
|
g.add_match(m3)
|
|
assert o1 is g.ref
|
|
assert g.prioritize(lambda x:x.name)
|
|
assert o3 is g.ref
|
|
|
|
def test_prioritize_with_tie_breaker(self):
|
|
# if the ref has the same key as one or more of the dupe, run the tie_breaker func among them
|
|
g = get_test_group()
|
|
o1, o2, o3 = g.ordered
|
|
tie_breaker = lambda ref, dupe: dupe is o3
|
|
g.prioritize(lambda x:0, tie_breaker)
|
|
assert g.ref is o3
|
|
|
|
def test_prioritize_with_tie_breaker_runs_on_all_dupes(self):
|
|
# Even if a dupe is chosen to switch with ref with a tie breaker, we still run the tie breaker
|
|
# with other dupes and the newly chosen ref
|
|
g = get_test_group()
|
|
o1, o2, o3 = g.ordered
|
|
o1.foo = 1
|
|
o2.foo = 2
|
|
o3.foo = 3
|
|
tie_breaker = lambda ref, dupe: dupe.foo > ref.foo
|
|
g.prioritize(lambda x:0, tie_breaker)
|
|
assert g.ref is o3
|
|
|
|
def test_prioritize_with_tie_breaker_runs_only_on_tie_dupes(self):
|
|
# The tie breaker only runs on dupes that had the same value for the key_func
|
|
g = get_test_group()
|
|
o1, o2, o3 = g.ordered
|
|
o1.foo = 2
|
|
o2.foo = 2
|
|
o3.foo = 1
|
|
o1.bar = 1
|
|
o2.bar = 2
|
|
o3.bar = 3
|
|
key_func = lambda x: -x.foo
|
|
tie_breaker = lambda ref, dupe: dupe.bar > ref.bar
|
|
g.prioritize(key_func, tie_breaker)
|
|
assert g.ref is o2
|
|
|
|
def test_prioritize_with_ref_dupe(self):
|
|
# when the ref dupe of a group is from a ref dir, make it stay on top.
|
|
g = get_test_group()
|
|
o1, o2, o3 = g
|
|
o1.is_ref = True
|
|
o2.size = 2
|
|
g.prioritize(lambda x: -x.size)
|
|
assert g.ref is o1
|
|
|
|
def test_prioritize_nothing_changes(self):
|
|
# prioritize() returns False when nothing changes in the group.
|
|
g = get_test_group()
|
|
g[0].name = 'a'
|
|
g[1].name = 'b'
|
|
g[2].name = 'c'
|
|
assert not g.prioritize(lambda x:x.name)
|
|
|
|
def test_list_like(self):
|
|
g = Group()
|
|
o1,o2 = (NamedObject("foo",True),NamedObject("bar",True))
|
|
g.add_match(get_match(o1,o2))
|
|
assert g[0] is o1
|
|
assert g[1] is o2
|
|
|
|
def test_discard_matches(self):
|
|
g = Group()
|
|
o1,o2,o3 = (NamedObject("foo",True),NamedObject("bar",True),NamedObject("baz",True))
|
|
g.add_match(get_match(o1,o2))
|
|
g.add_match(get_match(o1,o3))
|
|
g.discard_matches()
|
|
eq_(1,len(g.matches))
|
|
eq_(0,len(g.candidates))
|
|
|
|
|
|
class TestCaseget_groups:
|
|
def test_empty(self):
|
|
r = get_groups([])
|
|
eq_([],r)
|
|
|
|
def test_simple(self):
|
|
l = [NamedObject("foo bar"),NamedObject("bar bleh")]
|
|
matches = getmatches(l)
|
|
m = matches[0]
|
|
r = get_groups(matches)
|
|
eq_(1,len(r))
|
|
g = r[0]
|
|
assert g.ref is m.first
|
|
eq_([m.second],g.dupes)
|
|
|
|
def test_group_with_multiple_matches(self):
|
|
#This results in 3 matches
|
|
l = [NamedObject("foo"),NamedObject("foo"),NamedObject("foo")]
|
|
matches = getmatches(l)
|
|
r = get_groups(matches)
|
|
eq_(1,len(r))
|
|
g = r[0]
|
|
eq_(3,len(g))
|
|
|
|
def test_must_choose_a_group(self):
|
|
l = [NamedObject("a b"),NamedObject("a b"),NamedObject("b c"),NamedObject("c d"),NamedObject("c d")]
|
|
#There will be 2 groups here: group "a b" and group "c d"
|
|
#"b c" can go either of them, but not both.
|
|
matches = getmatches(l)
|
|
r = get_groups(matches)
|
|
eq_(2,len(r))
|
|
eq_(5,len(r[0])+len(r[1]))
|
|
|
|
def test_should_all_go_in_the_same_group(self):
|
|
l = [NamedObject("a b"),NamedObject("a b"),NamedObject("a b"),NamedObject("a b")]
|
|
#There will be 2 groups here: group "a b" and group "c d"
|
|
#"b c" can fit in both, but it must be in only one of them
|
|
matches = getmatches(l)
|
|
r = get_groups(matches)
|
|
eq_(1,len(r))
|
|
|
|
def test_give_priority_to_matches_with_higher_percentage(self):
|
|
o1 = NamedObject(with_words=True)
|
|
o2 = NamedObject(with_words=True)
|
|
o3 = NamedObject(with_words=True)
|
|
m1 = Match(o1, o2, 1)
|
|
m2 = Match(o2, o3, 2)
|
|
r = get_groups([m1,m2])
|
|
eq_(1,len(r))
|
|
g = r[0]
|
|
eq_(2,len(g))
|
|
assert o1 not in g
|
|
assert o2 in g
|
|
assert o3 in g
|
|
|
|
def test_four_sized_group(self):
|
|
l = [NamedObject("foobar") for i in range(4)]
|
|
m = getmatches(l)
|
|
r = get_groups(m)
|
|
eq_(1,len(r))
|
|
eq_(4,len(r[0]))
|
|
|
|
def test_referenced_by_ref2(self):
|
|
o1 = NamedObject(with_words=True)
|
|
o2 = NamedObject(with_words=True)
|
|
o3 = NamedObject(with_words=True)
|
|
m1 = get_match(o1,o2)
|
|
m2 = get_match(o3,o1)
|
|
m3 = get_match(o3,o2)
|
|
r = get_groups([m1,m2,m3])
|
|
eq_(3,len(r[0]))
|
|
|
|
def test_job(self):
|
|
def do_progress(p,d=''):
|
|
self.log.append(p)
|
|
return True
|
|
|
|
self.log = []
|
|
j = job.Job(1,do_progress)
|
|
m1,m2,m3 = get_match_triangle()
|
|
#101%: To make sure it is processed first so the job test works correctly
|
|
m4 = Match(NamedObject('a',True), NamedObject('a',True), 101)
|
|
get_groups([m1,m2,m3,m4],j)
|
|
eq_(0,self.log[0])
|
|
eq_(100,self.log[-1])
|
|
|
|
def test_group_admissible_discarded_dupes(self):
|
|
# If, with a (A, B, C, D) set, all match with A, but C and D don't match with B and that the
|
|
# (A, B) match is the highest (thus resulting in an (A, B) group), still match C and D
|
|
# in a separate group instead of discarding them.
|
|
A, B, C, D = [NamedObject() for _ in range(4)]
|
|
m1 = Match(A, B, 90) # This is the strongest "A" match
|
|
m2 = Match(A, C, 80) # Because C doesn't match with B, it won't be in the group
|
|
m3 = Match(A, D, 80) # Same thing for D
|
|
m4 = Match(C, D, 70) # However, because C and D match, they should have their own group.
|
|
groups = get_groups([m1, m2, m3, m4])
|
|
eq_(len(groups), 2)
|
|
g1, g2 = groups
|
|
assert A in g1
|
|
assert B in g1
|
|
assert C in g2
|
|
assert D in g2
|
|
|